A meeting has to be conducted with 3 managers.

A meeting has to be conducted with 3 managers. Find the number of ways in which the managers be selected from among 6 managers, if 2 managers will not attend the meeting together?

Quiz

Answer/Solution

16

Steps/Work

we can either choose all 3 people from 4 manager who have no problems or choose 2 from the 4 and 1 from the 2 managers who have a problem sitting together
so 4C3 + (4C2 * 2C1)
this is 4 + 12=16
Answer : C

Probability Calculator / Auto Solver

A meeting has to be conducted with managers. Find the number of ways in which the managers be selected from among managers, if managers will not attend the meeting together?

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