When 242 is divided by a certain divisor the remainder obtained is 15.
When 242 is divided by a certain divisor the remainder obtained is 15. When 698 is divided by the same divisor the remainder obtained is 27. However, when the sum of the two numbers 242 and 698 is divided by the divisor, the remainder obtained is 5. What is the value of the divisor?
Answer/Solution
37
Steps/Work
let that divisor be x
since remainder is 15 or 27 it means divisor is greater than 27.
now 242-15=227 =kx (k is an integer and 234 is divisble by x)
similarly 698-27=671 = lx (l is an integer and 689 is divisible by x)
adding both 698 and 242
= (227+671)+15+27
=x(k+l) + 42
when we divide this number by x then remainder will be equal to remainder of (42 divided by x) = 5 hence x = 42-5 = 37
hence E
since remainder is 15 or 27 it means divisor is greater than 27.
now 242-15=227 =kx (k is an integer and 234 is divisble by x)
similarly 698-27=671 = lx (l is an integer and 689 is divisible by x)
adding both 698 and 242
= (227+671)+15+27
=x(k+l) + 42
when we divide this number by x then remainder will be equal to remainder of (42 divided by x) = 5 hence x = 42-5 = 37
hence E