A group of n students can be divided into equal groups of 4 with 1 student left over or equal groups...
A group of n students can be divided into equal groups of 4 with 1 student left over or equal groups of 5 with 2 students left over. What is the sum of the two smallest possible values of n?
Answer/Solution
54
Steps/Work
n = 4k+1 = 5j+2
Let's start at 1 = 4(0)+1 and keep adding 4 until we find a number in the form 5j+2.
1, 5, 9, 13, 17 = 5(3)+2
The next such number is 17 + 4*5 = 37.
17+37 = 54
The answer is D.
Let's start at 1 = 4(0)+1 and keep adding 4 until we find a number in the form 5j+2.
1, 5, 9, 13, 17 = 5(3)+2
The next such number is 17 + 4*5 = 37.
17+37 = 54
The answer is D.