Two trains, each 100 m long, moving in opposite directions, cross other in 10 sec.

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Two trains, each m long, moving in opposite directions, cross other in sec. If one is moving twice as fast the other, then the speed of the faster train is?

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Calculated Answer

48

Step by Step Solution

In order to solve problem, you must evaluate ((n₀ + n₀) / (n₁ * (1 + 2)) * 2 * 3600) / 1000.

• ((n₀ + n₀) / (n₁ * (1 + 2)) * 2 * 3600) / 1000

• Evaluate n₀ + n₀ = 200

  (200 / (n₁ * (1 + 2)) * 2 * 3600) / 1000

• Evaluate 1 + 2 = 3

  (200 / (n₁ * 3) * 2 * 3600) / 1000

• Evaluate n₁ * 3 = 30

  (200 / 30 * 2 * 3600) / 1000

• Evaluate 200 / 30 = 6.6666666666667

  (6.6666666666667 * 2 * 3600) / 1000

• Evaluate 6.6666666666667 * 2 = 13.333333333333

  (13.333333333333 * 3600) / 1000

• Evaluate 13.333333333333 * 3600 = 48000

  48000 / 1000

• Evaluate 48000 / 1000 = 48

  48
• The answer to the problem and the result of ((n₀ + n₀) / (n₁ * (1 + 2)) * 2 * 3600) / 1000 is 48