In a simultaneous throw of a pair of dice, find the probability of getting a total more than 10
In a simultaneous throw of a pair of dice, find the probability of getting a total more than 10
Answer/Solution
1 by 12
Steps/Work
Total number of cases = 6*6 = 36
Favourable cases = [(5,6)(6,5),(6,6)] = 3
So Probability = 3/36 = 1/12
Answer is C
Favourable cases = [(5,6)(6,5),(6,6)] = 3
So Probability = 3/36 = 1/12
Answer is C