A thief steals at a car at 3.30 p.m. and drives it at 60 km/hr.
A thief steals at a car at 3.30 p.m. and drives it at 60 km/hr. The theft is discovered at 3 p.m. and the owner sets off in another car at 75 km/hr. When will he overtake the thief?
Answer/Solution
6 p.m
Steps/Work
E
6 p.m
Suppose the thief is overtaken x hrs after 3.30 p.m.
Then, distance covered by the owner in (x - 1/2) hrs.
60x = 75(x - 1/2) => x = 5/2 hrs.
So, the thief is overtaken at 6 p.m.
6 p.m
Suppose the thief is overtaken x hrs after 3.30 p.m.
Then, distance covered by the owner in (x - 1/2) hrs.
60x = 75(x - 1/2) => x = 5/2 hrs.
So, the thief is overtaken at 6 p.m.