If x = -5 and y = 8, what is the value of 2(x-y)^2 - xy ?
If x = -5 and y = 8, what is the value of 2(x-y)^2 - xy ?
Answer/Solution
378
Steps/Work
x = -5 and y = 8
x-y = -5 - 8 = -13
x*y = -5 * 8 = -40
Now we apply it in the equation 2(x-y)^2 - xy =2(-13)^2-(-40)
==>2*169 +40 = 338+40 =378
Answer : E
x-y = -5 - 8 = -13
x*y = -5 * 8 = -40
Now we apply it in the equation 2(x-y)^2 - xy =2(-13)^2-(-40)
==>2*169 +40 = 338+40 =378
Answer : E