Kim bought a total of $4.65 worth of postage stamps in four denominations.
Kim bought a total of $4.65 worth of postage stamps in four denominations. If she bought an equal number of 10-cent and 25-cent stamps and twice as many 20-cent stamps as 5-cent stamps, what is the least number of 1-cent stamps she could have bought?
Answer/Solution
90
Steps/Work
Let:
# of 10 and 25 cents stamps = n
# of 20 cent stamps = 2n
# of 1 cent stamps = m
Therefore:
10n + 25n + 20(2n) + m = 465 cents
75n + m = 465
Forleastnumber of 1 cents stamps, maximize 50n. Hence,
75*5 + m = 465
m = 90 i.e. 90 stamps 1 cents each
Answer: D
# of 10 and 25 cents stamps = n
# of 20 cent stamps = 2n
# of 1 cent stamps = m
Therefore:
10n + 25n + 20(2n) + m = 465 cents
75n + m = 465
Forleastnumber of 1 cents stamps, maximize 50n. Hence,
75*5 + m = 465
m = 90 i.e. 90 stamps 1 cents each
Answer: D