# A computer is programmed to multiply consecutive even integers 2*4*6*8*…*n until the product is ...

A computer is programmed to multiply consecutive even integers 2*4*6*8*…*n until the product is divisible by 1881, What is the value of n?

## Answer/Solution

114

### Steps/Work

Factorise 1881.. 3*11*57..

So n has to be a multiple of largest prime number,61..

So n=2*57=114..

Ans :C

So n has to be a multiple of largest prime number,61..

So n=2*57=114..

Ans :C