For 6-digit integer 46x,y12, when x and y are drawn at random from {3,5,8}, what is the probability ...
For 6-digit integer 46x,y12, when x and y are drawn at random from {3,5,8}, what is the probability W that the integer drawn is divisible by 8?
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Answer/Solution
2/3
Steps/Work
In general, the remainder divided by integer n is the same as the remainder that up to tens of n is divided by 8.
Thus, in order for 46,x,y12 to be divided by 8, y12 should be divided by 8.
Amongst 3,5,8, 3 and 5 can be divided by 8.
Therefore,W= two out of three can be divided and the answer is D.
Thus, in order for 46,x,y12 to be divided by 8, y12 should be divided by 8.
Amongst 3,5,8, 3 and 5 can be divided by 8.
Therefore,W= two out of three can be divided and the answer is D.