# Ron cycles his way up on a hill side and back.

Ron cycles his way up on a hill side and back. He takes the exact same route both ways. On the trip out he cycles an average speed of 5 miles per hour. On the trip back, downhill cycling at an average speed of 100 miles per hour, he is quick to return back. What is his approximate average speed for the round trip in miles per hour?

## Answer/Solution

9.52

### Steps/Work

Average speed = total distance/total time

Here distance to hill top and back is same as he takes the same route.

D = 5T1 and D=100T2

Therefore, T1 = D/5 and T2 = D/100

T1+T2 = 21d/100

Therefore, average speed = 2d/21d/100 =2d * 100/21d

Answer is 9.52 Since, the options are far away we need not solve till the decimal points

So correct answer is option B

Here distance to hill top and back is same as he takes the same route.

D = 5T1 and D=100T2

Therefore, T1 = D/5 and T2 = D/100

T1+T2 = 21d/100

Therefore, average speed = 2d/21d/100 =2d * 100/21d

Answer is 9.52 Since, the options are far away we need not solve till the decimal points

So correct answer is option B