A can do a piece of work in 18 days, B in 27 days, C in 36 days.
A can do a piece of work in 18 days, B in 27 days, C in 36 days. They start worked together . But only C work till the completion of work. A leaves 4 days and B leaves 6 days before the completion of work. In how many days work be completed?
Answer/Solution
12
Steps/Work
Let the work be completed in x days
(x-4)days of A + (x-6)days of B + x days of C = 1
\inline \Rightarrow \inline \frac{x-4}{18}+\frac{x-6}{27}+\frac{x}{36}=1
\inline \Rightarrow \frac{13x-48}{108}=1
x = 12
\inline \therefore Total time = 12 days
Answer:A
(x-4)days of A + (x-6)days of B + x days of C = 1
\inline \Rightarrow \inline \frac{x-4}{18}+\frac{x-6}{27}+\frac{x}{36}=1
\inline \Rightarrow \frac{13x-48}{108}=1
x = 12
\inline \therefore Total time = 12 days
Answer:A