A and B together do a work in 20 days.B and C together in 15 days and C and A in 12 days.then B ...
A and B together do a work in 20 days.B and C together in 15 days and C and A in 12 days.then B alone can finish same work in how many days?
Answer/Solution
60
Steps/Work
(A+B) work in 1 day= 1/20,(B+C) work in 1 days = 1/15.,(C+A) work in 1 days=1/12
(1) adding=2[A+B+C] in 1 day work = [1/20+1/15+1/12]=1/5
(A+B+C) work in 1 day= 1/10
B work in 1 days= [A+B+C] work in 1 days- work of (A+C) in 1 days
=[1/10-1/12]=1/60
B alone finish work in 60 days
Answer B
(1) adding=2[A+B+C] in 1 day work = [1/20+1/15+1/12]=1/5
(A+B+C) work in 1 day= 1/10
B work in 1 days= [A+B+C] work in 1 days- work of (A+C) in 1 days
=[1/10-1/12]=1/60
B alone finish work in 60 days
Answer B