# All the milk in container A which was filled to its brim was poured into two containers B and C.

All the milk in container A which was filled to its brim was poured into two containers B and C. The quantity of milk in container B was 62.5% less than the capacity of container A. If 158 liters was now transferred from C to B, then both the containers would have equal quantities of milk. What was the initial quantity of milk in container A?

## Answer/Solution

1264

### Steps/Work

A

B has 62.5% or (5/8) of the milk in A. Therefore, let the quantity of milk in container A(initially) be 8k.

Quantity of milk in B = 8k - 5k = 3k.

Quantity of milk in container C = 8k - 3k = 5k

Container: A B C

Quantity of milk: 8k 3k 5k

It is given that if 158 liters was transferred from container C to container B, then both the containers would have equal quantities of milk.

5k - 158 = 3k + 158 => 2k =316 => k = 158

The initial quantity of milk in A = 8k = 8 * 158 = 1264 liters.

B has 62.5% or (5/8) of the milk in A. Therefore, let the quantity of milk in container A(initially) be 8k.

Quantity of milk in B = 8k - 5k = 3k.

Quantity of milk in container C = 8k - 3k = 5k

Container: A B C

Quantity of milk: 8k 3k 5k

It is given that if 158 liters was transferred from container C to container B, then both the containers would have equal quantities of milk.

5k - 158 = 3k + 158 => 2k =316 => k = 158

The initial quantity of milk in A = 8k = 8 * 158 = 1264 liters.