if log 2 = 0.30103 and log 3 = 0.4771, find the number of digits in (648)5

log(648)5
= 5 log(648)
= 5 log(81 × 8)
= 5[log(81) + log(8)]
=5 [log(34) + log(23)]
=5[4log(3) + 3log(2)]
= 5[4 × 0.4771 + 3 × 0.30103]
= 5(1.9084 + 0.90309)
= 5 × 2.81149
≈ 14.05
Answer: A