If k = 2n - 1, where n is an integer, what is the remainder of k^2/8?
If k = 2n - 1, where n is an integer, what is the remainder of k^2/8?
Answer/Solution
1
Steps/Work
Let us assume that k = 4(n)(n-1)
This is divisible by 8.
So k+1 when divided by 8 will give reminder 1.
For example, consider n = 2
We have 4*2*1 + 1 = 9
When we divide this by 8 we get reminder 1.
ANSWER:A
This is divisible by 8.
So k+1 when divided by 8 will give reminder 1.
For example, consider n = 2
We have 4*2*1 + 1 = 9
When we divide this by 8 we get reminder 1.
ANSWER:A