What is the absolute value of twice the difference of the roots of the equation W=5y^2 − 20y + 15 ...
What is the absolute value of twice the difference of the roots of the equation W=5y^2 − 20y + 15 = 0 ?
Answer/Solution
4
Steps/Work
W=5y^2 − 20y + 15 = 0 --> y^2 − 4y + 3 = 0 --> y=1 or y=3. The difference is 2, twice the difference is 4.
Answer: E.
Answer: E.