The sum of the first 50 positive even integers is 2550.
The sum of the first 50 positive even integers is 2550. What is the sum E of even integers from 102 to 200 inclusive?
Answer/Solution
7550
Steps/Work
My solution is:
First 50 even integers:
2
4
6
8
<...>
Integers from 102 to 200
102
104
106
108
<...>
We notice that each integer from the second set is 100 more than the respective integer in the first set. Since we have 50 even integers from 102 to 200, then:
E=2550+(100*50)=7550.B
First 50 even integers:
2
4
6
8
<...>
Integers from 102 to 200
102
104
106
108
<...>
We notice that each integer from the second set is 100 more than the respective integer in the first set. Since we have 50 even integers from 102 to 200, then:
E=2550+(100*50)=7550.B