A shopkeeper bought 600 oranges and 400 bananas.
A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 7% of bananas were rotten. Find the percentage of fruits in good condition?
Answer/Solution
88.2%
Steps/Work
Total number of fruits shopkeeper bought = 600 + 400 = 1000
Number of rotten oranges = 15% of 600
= 15/100 × 600
= 9000/100
= 90
Number of rotten bananas = 7% of 400
= 28
Therefore, total number of rotten fruits = 90 + 28= 118
Therefore Number of fruits in good condition = 1000 - 118 = 882
Therefore Percentage of fruits in good condition = (882/1000 × 100)%
= (88200/1000)%
= 88.2%
Answer:B
Number of rotten oranges = 15% of 600
= 15/100 × 600
= 9000/100
= 90
Number of rotten bananas = 7% of 400
= 28
Therefore, total number of rotten fruits = 90 + 28= 118
Therefore Number of fruits in good condition = 1000 - 118 = 882
Therefore Percentage of fruits in good condition = (882/1000 × 100)%
= (88200/1000)%
= 88.2%
Answer:B