If a refrigerator contains 12 cans such that there are 7 blue cans and 5 red cans.
If a refrigerator contains 12 cans such that there are 7 blue cans and 5 red cans. In how many ways can we remove 8 cans so that at least 1 blue can and 1 red can remains in the refrigerator.
Answer/Solution
455
Steps/Work
The possible cases of (b,r) draws are (6,2) (5,3) (4,4)
6 2---->7c6*5c2--->7*10=70
5 3---->7c5*5c3--->21*10=210
4 4---->7c4*5c4--->35*5=175
70+210+175=455
ANSWER:D
6 2---->7c6*5c2--->7*10=70
5 3---->7c5*5c3--->21*10=210
4 4---->7c4*5c4--->35*5=175
70+210+175=455
ANSWER:D