The present ages of three persons in proportions 4 : 1 : 3.
The present ages of three persons in proportions 4 : 1 : 3. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Answer/Solution
40, 10, 30
Steps/Work
Let their present ages be 4x, x and 3x years respectively.
Then, (4x - 8) + (x - 8) + (3x - 8) = 56
8x = 80
x = 10.
Their present ages are 4x = 40 years, 1x = 10 years and 3x = 30 years respectively.
Answer:D
Then, (4x - 8) + (x - 8) + (3x - 8) = 56
8x = 80
x = 10.
Their present ages are 4x = 40 years, 1x = 10 years and 3x = 30 years respectively.
Answer:D