An old man distributed all the gold coins he had to his two sons into two different numbers such ...

An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 81 times the difference between the two numbers. How many coins did the old man have?

Quiz

Answer/Solution

81

Steps/Work

Let the number of coins one son got be x and the number of coins another got be y. Total = x + y.
x^2 - y^2 = 81(x - y) --> x + y = 81.
Answer: D.

General Calculator / Auto Solver

An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is times the difference between the two numbers. How many coins did the old man have?

Calculated Answer

81

Step by Step Solution

In order to solve problem, you must evaluate floor(n0).

n0 =81