On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer).
On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 5 cups of tea. Last week Mo drank a total of 22 cups of tea and hot chocolate together. If during that week Mo drank 8 more tea cups than hot chocolate cups, then how many rainy days were there last week?
Answer/Solution
4
Steps/Work
T= the number of cups of tea
C= the number of cups of hot chocolate
T+C = 22 T-C=8 -> T= 15. C=7.
Mo drinks 5 cups of tea a day then number of days that are not rainy = 15/5 = 3
So number of rainy days = 7-3 = 4
B is the answer.
C= the number of cups of hot chocolate
T+C = 22 T-C=8 -> T= 15. C=7.
Mo drinks 5 cups of tea a day then number of days that are not rainy = 15/5 = 3
So number of rainy days = 7-3 = 4
B is the answer.