x varies inversely as square of y.
x varies inversely as square of y. Given that y=3 for x=1. The value of x for y = 4 will be equal to:
Answer/Solution
9/16
Steps/Work
Explanation :
Solution: Given x = k/y^2, where k is constant. Now, y=3 and x =1 gives k = 9.
.'. x = 9/y^2
=> x =9 /4^2 = 9/16
Answer : E
Solution: Given x = k/y^2, where k is constant. Now, y=3 and x =1 gives k = 9.
.'. x = 9/y^2
=> x =9 /4^2 = 9/16
Answer : E