If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 ...
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer/Solution
4
Steps/Work
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y
Then, 6x + 8y = 1/10 and 26x + 48y = 1/2
Solving these two equations, we get : x = 1/100 and y = 1/200
15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4
15 men and 20 boys can do the work in 4 days.
Answer: C
Then, 6x + 8y = 1/10 and 26x + 48y = 1/2
Solving these two equations, we get : x = 1/100 and y = 1/200
15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4
15 men and 20 boys can do the work in 4 days.
Answer: C