If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the ...
If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 4?
Answer/Solution
3/4
Steps/Work
I get 5/8 as well
1 to 96 inclusive means we have 48 odd and 48 even integers
E O E / 4 = Integer, therefore we have 48 / 96 numbers divisible by 8
O E O / 4 = Not Integer
We cannot forget multiples of 8 from 1 to 96
We have 24 numbers that are multiple of 4
Therefore, 48/96 + 24/96 = 72/96 = 3/4
answer : E
1 to 96 inclusive means we have 48 odd and 48 even integers
E O E / 4 = Integer, therefore we have 48 / 96 numbers divisible by 8
O E O / 4 = Not Integer
We cannot forget multiples of 8 from 1 to 96
We have 24 numbers that are multiple of 4
Therefore, 48/96 + 24/96 = 72/96 = 3/4
answer : E