How many pounds of salt at 50 cents/lb must be mixed with 40 lbs of salt that costs 38 cents/lb so ...

How many pounds of salt at 50 cents/lb must be mixed with 40 lbs of salt that costs 38 cents/lb so that a merchant will get 20% profit by selling the mixture at 48 cents/lb?

Quiz

Answer/Solution

8

Steps/Work

Selling price is 48 cents/lb
For a 20% profit, cost price should be 40 cents/lb (CP*6/5 = 48)
Basically, you need to mix 38 cents/lb (Salt 1) with 50 cents/lb (Salt 2) to get a mixture costing 40 cents/lb (Salt Avg)
weight of Salt1/weight of Salt2 = (Salt2 - SaltAvg)/(SaltAvg - Salt1) = (50 - 40)/(40 - 38) = 5/1
We know that weight of salt 1 is 40 lbs. Weight of salt 2 must be 8 lbs.
Answer (C)

Gain Calculator / Auto Solver

How many pounds of salt at cents / lb must be mixed with lbs of salt that costs cents / lb so that a merchant will get % profit by selling the mixture at cents / lb?

Calculated Answer

8

Step by Step Solution

In order to solve problem, you must evaluate (n1 * n4 - (n3 + 100) / 100 * n1 * n2) / (n0 * (n3 + 100) / 100 - n4).

n0 =50
n1 =40
n2 =38
n3 =20
n4 =48