If a = 1 and b = -2, then (2a^2 + b)(t + y) + (a + b)(t - y) =
If a = 1 and b = -2, then (2a^2 + b)(t + y) + (a + b)(t - y) =
Answer/Solution
y - t
Steps/Work
Putting A=1 and B = -2 => 2A^2-B=0 ; so the first part of the term is zero
with second term => (1-2) *(t+y)=y-t => Smash C
with second term => (1-2) *(t+y)=y-t => Smash C